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132311034109951 is a prime number
BaseRepresentation
bin11110000101011000010000…
…001100000001111111111111
3122100110210220110102000202221
4132011120100030001333333
5114320240444213004301
61145222503331230211
736604104524422024
oct3605302014017777
9570423813360687
10132311034109951
1139181881460444
1212a0a921748367
1358a9b529563a8
142495c613bd54b
151046aa87b0da1
hex785610301fff

132311034109951 has 2 divisors, whose sum is σ = 132311034109952. Its totient is φ = 132311034109950.

The previous prime is 132311034109937. The next prime is 132311034109979. The reversal of 132311034109951 is 159901430113231.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (159901430113231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132311034109951 - 27 = 132311034109823 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132311034109898 and 132311034109907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132311034109901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66155517054975 + 66155517054976.

It is an arithmetic number, because the mean of its divisors is an integer number (66155517054976).

Almost surely, 2132311034109951 is an apocalyptic number.

132311034109951 is a deficient number, since it is larger than the sum of its proper divisors (1).

132311034109951 is an equidigital number, since it uses as much as digits as its factorization.

132311034109951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 43.

The spelling of 132311034109951 in words is "one hundred thirty-two trillion, three hundred eleven billion, thirty-four million, one hundred nine thousand, nine hundred fifty-one".