Base | Representation |
---|---|
bin | 10011010000001111101… |
… | …100110110010001011100 |
3 | 11200111012001011212212111 |
4 | 103100033230312101130 |
5 | 133134214003421134 |
6 | 2451455130443404 |
7 | 164406660562264 |
oct | 23201754662134 |
9 | 4614161155774 |
10 | 1323113342044 |
11 | 470146a9616a |
12 | 194517b93564 |
13 | 979cc7bbbb0 |
14 | 4807913c7a4 |
15 | 2463d172c64 |
hex | 1340fb3645c |
1323113342044 has 24 divisors (see below), whose sum is σ = 2494270317728. Its totient is φ = 610493682240.
The previous prime is 1323113342017. The next prime is 1323113342053. The reversal of 1323113342044 is 4402433113231.
It is a junction number, because it is equal to n+sod(n) for n = 1323113341997 and 1323113342015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3440967 + ... + 3806110.
Almost surely, 21323113342044 is an apocalyptic number.
It is an amenable number.
1323113342044 is a deficient number, since it is larger than the sum of its proper divisors (1171156975684).
1323113342044 is a wasteful number, since it uses less digits than its factorization.
1323113342044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7250605 (or 7250603 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 1323113342044 its reverse (4402433113231), we get a palindrome (5725546455275).
The spelling of 1323113342044 in words is "one trillion, three hundred twenty-three billion, one hundred thirteen million, three hundred forty-two thousand, forty-four".
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