Base | Representation |
---|---|
bin | 1100000010001001111011… |
… | …0010001101011011011110 |
3 | 1201211212221111220112020021 |
4 | 3000202132302031123132 |
5 | 3213234410241442024 |
6 | 44050151254542354 |
7 | 2533630362564145 |
oct | 300423662153336 |
9 | 51755844815207 |
10 | 13231163234014 |
11 | 4241339789950 |
12 | 15983559679ba |
13 | 74c90236031b |
14 | 33a56ac3075c |
15 | 17e28d90bde4 |
hex | c089ec8d6de |
13231163234014 has 16 divisors (see below), whose sum is σ = 22111653839616. Its totient is φ = 5886204146200.
The previous prime is 13231163233993. The next prime is 13231163234017. The reversal of 13231163234014 is 41043236113231.
13231163234014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×132311632340142 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13231163234017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6398046952 + ... + 6398049019.
It is an arithmetic number, because the mean of its divisors is an integer number (1381978364976).
Almost surely, 213231163234014 is an apocalyptic number.
13231163234014 is a deficient number, since it is larger than the sum of its proper divisors (8880490605602).
13231163234014 is a wasteful number, since it uses less digits than its factorization.
13231163234014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12796096031.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 13231163234014 its reverse (41043236113231), we get a palindrome (54274399347245).
The spelling of 13231163234014 in words is "thirteen trillion, two hundred thirty-one billion, one hundred sixty-three million, two hundred thirty-four thousand, fourteen".
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