Base | Representation |
---|---|
bin | 111101100111001101… |
… | …1000110100101010111 |
3 | 110122112001210201012112 |
4 | 1323032123012211113 |
5 | 4131433412331411 |
6 | 140441114141235 |
7 | 12362551254236 |
oct | 1731633064527 |
9 | 418461721175 |
10 | 132312230231 |
11 | 51127893a05 |
12 | 2178712181b |
13 | c627c3c6bc |
14 | 65925dcb1d |
15 | 3695d4db8b |
hex | 1ece6c6957 |
132312230231 has 2 divisors, whose sum is σ = 132312230232. Its totient is φ = 132312230230.
The previous prime is 132312230227. The next prime is 132312230261. The reversal of 132312230231 is 132032213231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132312230231 - 22 = 132312230227 is a prime.
It is a super-2 number, since 2×1323122302312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132312230197 and 132312230206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132312230261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156115115 + 66156115116.
It is an arithmetic number, because the mean of its divisors is an integer number (66156115116).
Almost surely, 2132312230231 is an apocalyptic number.
132312230231 is a deficient number, since it is larger than the sum of its proper divisors (1).
132312230231 is an equidigital number, since it uses as much as digits as its factorization.
132312230231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 132312230231 its reverse (132032213231), we get a palindrome (264344443462).
The spelling of 132312230231 in words is "one hundred thirty-two billion, three hundred twelve million, two hundred thirty thousand, two hundred thirty-one".
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