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132313211207 = 177783130071
BaseRepresentation
bin111101100111001111…
…0110110000101000111
3110122112010122112211222
41323032132312011013
54131434140224312
6140441151150555
712362562511232
oct1731636660507
9418463575758
10132313211207
11511283a3a31
122178751545b
13c6281c4068
1465927b6419
153695e94672
hex1ece7b6147

132313211207 has 4 divisors (see below), whose sum is σ = 140096341296. Its totient is φ = 124530081120.

The previous prime is 132313211183. The next prime is 132313211209. The reversal of 132313211207 is 702112313231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132313211207 - 28 = 132313210951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132313211209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3891565019 + ... + 3891565052.

It is an arithmetic number, because the mean of its divisors is an integer number (35024085324).

Almost surely, 2132313211207 is an apocalyptic number.

132313211207 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

132313211207 is a deficient number, since it is larger than the sum of its proper divisors (7783130089).

132313211207 is an equidigital number, since it uses as much as digits as its factorization.

132313211207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7783130088.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 132313211207 its reverse (702112313231), we get a palindrome (834425524438).

The spelling of 132313211207 in words is "one hundred thirty-two billion, three hundred thirteen million, two hundred eleven thousand, two hundred seven".

Divisors: 1 17 7783130071 132313211207