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132315166065541 is a prime number
BaseRepresentation
bin11110000101011100000110…
…011110001100001110000101
3122100111012120102102010021011
4132011130012132030032011
5114320322430003044131
61145224425333322221
736604312106442544
oct3605340636141605
9570435512363234
10132315166065541
1139183601881878
1212a0b695496371
1358aa3609c9724
14249613408215b
151046c4b3ee0b1
hex78570678c385

132315166065541 has 2 divisors, whose sum is σ = 132315166065542. Its totient is φ = 132315166065540.

The previous prime is 132315166065539. The next prime is 132315166065557. The reversal of 132315166065541 is 145560661513231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116029736324100 + 16285429741441 = 10771710^2 + 4035521^2 .

It is a cyclic number.

It is not a de Polignac number, because 132315166065541 - 21 = 132315166065539 is a prime.

Together with 132315166065539, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132315166065581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157583032770 + 66157583032771.

It is an arithmetic number, because the mean of its divisors is an integer number (66157583032771).

Almost surely, 2132315166065541 is an apocalyptic number.

It is an amenable number.

132315166065541 is a deficient number, since it is larger than the sum of its proper divisors (1).

132315166065541 is an equidigital number, since it uses as much as digits as its factorization.

132315166065541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 49.

The spelling of 132315166065541 in words is "one hundred thirty-two trillion, three hundred fifteen billion, one hundred sixty-six million, sixty-five thousand, five hundred forty-one".