Base | Representation |
---|---|
bin | 10011010000010101011… |
… | …101100111010111011111 |
3 | 11200111102210002020021221 |
4 | 103100111131213113133 |
5 | 133134413230342002 |
6 | 2451512502434211 |
7 | 164412243345253 |
oct | 23202535472737 |
9 | 4614383066257 |
10 | 1323210012127 |
11 | 4701966128a3 |
12 | 194544432967 |
13 | 97a16837b23 |
14 | 48087d04263 |
15 | 246468bac37 |
hex | 134157675df |
1323210012127 has 2 divisors, whose sum is σ = 1323210012128. Its totient is φ = 1323210012126.
The previous prime is 1323210012067. The next prime is 1323210012167. The reversal of 1323210012127 is 7212100123231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1323210012127 - 219 = 1323209487839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323210012167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661605006063 + 661605006064.
It is an arithmetic number, because the mean of its divisors is an integer number (661605006064).
Almost surely, 21323210012127 is an apocalyptic number.
1323210012127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323210012127 is an equidigital number, since it uses as much as digits as its factorization.
1323210012127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1323210012127 its reverse (7212100123231), we get a palindrome (8535310135358).
The spelling of 1323210012127 in words is "one trillion, three hundred twenty-three billion, two hundred ten million, twelve thousand, one hundred twenty-seven".
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