1323210012167 has 2 divisors, whose sum is σ = 1323210012168. Its totient is φ = 1323210012166.

The previous prime is 1323210012127. The next prime is 1323210012169. The reversal of 1323210012167 is 7612100123231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1323210012167 - 2¹⁰ = 1323210011143 is a prime.

Together with 1323210012169, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1323210012169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661605006083 + 661605006084.

It is an arithmetic number, because the mean of its divisors is an integer number (661605006084).

Almost surely, 2^{1323210012167} is an apocalyptic number.

1323210012167 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323210012167 is an equidigital number, since it uses as much as digits as its factorization.

1323210012167 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 29.

Adding to 1323210012167 its reverse (7612100123231), we get a palindrome (8935310135398).

The spelling of 1323210012167 in words is "one trillion, three hundred twenty-three billion, two hundred ten million, twelve thousand, one hundred sixty-seven".