Base | Representation |
---|---|
bin | 10011010000010101011… |
… | …101100111010111100100 |
3 | 11200111102210002020022010 |
4 | 103100111131213113210 |
5 | 133134413230342012 |
6 | 2451512502434220 |
7 | 164412243345261 |
oct | 23202535472744 |
9 | 4614383066263 |
10 | 1323210012132 |
11 | 4701966128a8 |
12 | 194544432970 |
13 | 97a16837b28 |
14 | 48087d04268 |
15 | 246468bac3c |
hex | 134157675e4 |
1323210012132 has 48 divisors (see below), whose sum is σ = 3197314233792. Its totient is φ = 425653687680.
The previous prime is 1323210012127. The next prime is 1323210012167. The reversal of 1323210012132 is 2312100123231.
It is a junction number, because it is equal to n+sod(n) for n = 1323210012099 and 1323210012108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17014638 + ... + 17092229.
It is an arithmetic number, because the mean of its divisors is an integer number (66610713204).
Almost surely, 21323210012132 is an apocalyptic number.
1323210012132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1323210012132 is an abundant number, since it is smaller than the sum of its proper divisors (1874104221660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1323210012132 is a wasteful number, since it uses less digits than its factorization.
1323210012132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34106988 (or 34106986 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1323210012132 its reverse (2312100123231), we get a palindrome (3635310135363).
The spelling of 1323210012132 in words is "one trillion, three hundred twenty-three billion, two hundred ten million, twelve thousand, one hundred thirty-two".
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