132321121021 has 4 divisors (see below), whose sum is σ = 133996072000. Its totient is φ = 130646170044.

The previous prime is 132321121019. The next prime is 132321121061. The reversal of 132321121021 is 120121123231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 120121123231 = 3323 ⋅36148397.

It is a cyclic number.

It is not a de Polignac number, because 132321121021 - 2¹ = 132321121019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132321121021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132321121061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 837475371 + ... + 837475528.

It is an arithmetic number, because the mean of its divisors is an integer number (33499018000).

Almost surely, 2^132321121021 is an apocalyptic number.

It is an amenable number.

132321121021 is a deficient number, since it is larger than the sum of its proper divisors (1674950979).

132321121021 is an equidigital number, since it uses as much as digits as its factorization.

132321121021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1674950978.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132321121021 its reverse (120121123231), we get a palindrome (252442244252).

It can be divided in two parts, 132 and 321121021, that added together give a triangular number (321121153 = T₂₅₃₄₂).

The spelling of 132321121021 in words is "one hundred thirty-two billion, three hundred twenty-one million, one hundred twenty-one thousand, twenty-one".