Base | Representation |
---|---|
bin | 111101100111011110… |
… | …1000011101000001111 |
3 | 110122112200112220210111 |
4 | 1323032331003220033 |
5 | 4131443202143043 |
6 | 140442033020451 |
7 | 12363020025124 |
oct | 1731675035017 |
9 | 418480486714 |
10 | 132321131023 |
11 | 51131913234 |
12 | 2178a0b4727 |
13 | c629a37b43 |
14 | 659387874b |
15 | 3696a0b09d |
hex | 1ecef43a0f |
132321131023 has 2 divisors, whose sum is σ = 132321131024. Its totient is φ = 132321131022.
The previous prime is 132321131021. The next prime is 132321131029. The reversal of 132321131023 is 320131123231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132321131023 - 21 = 132321131021 is a prime.
Together with 132321131021, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 132321130985 and 132321131003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132321131021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160565511 + 66160565512.
It is an arithmetic number, because the mean of its divisors is an integer number (66160565512).
Almost surely, 2132321131023 is an apocalyptic number.
132321131023 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321131023 is an equidigital number, since it uses as much as digits as its factorization.
132321131023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 132321131023 its reverse (320131123231), we get a palindrome (452452254254).
The spelling of 132321131023 in words is "one hundred thirty-two billion, three hundred twenty-one million, one hundred thirty-one thousand, twenty-three".
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