Base | Representation |
---|---|
bin | 11110000101100001101011… |
… | …011000011100110010010011 |
3 | 122100111210000201211001200021 |
4 | 132011201223120130302103 |
5 | 114320422210412323033 |
6 | 1145231255440204311 |
7 | 36604613356330231 |
oct | 3605415330346223 |
9 | 570453021731607 |
10 | 132321154026643 |
11 | 391860a492a65a |
12 | 12a10886909697 |
13 | 58aaaa643b88a |
14 | 2496541439951 |
15 | 1046e9be59b2d |
hex | 78586b61cc93 |
132321154026643 has 2 divisors, whose sum is σ = 132321154026644. Its totient is φ = 132321154026642.
The previous prime is 132321154026641. The next prime is 132321154026673. The reversal of 132321154026643 is 346620451123231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132321154026643 - 21 = 132321154026641 is a prime.
Together with 132321154026641, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 132321154026643.
It is not a weakly prime, because it can be changed into another prime (132321154026641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160577013321 + 66160577013322.
It is an arithmetic number, because the mean of its divisors is an integer number (66160577013322).
Almost surely, 2132321154026643 is an apocalyptic number.
132321154026643 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321154026643 is an equidigital number, since it uses as much as digits as its factorization.
132321154026643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 43.
The spelling of 132321154026643 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, one hundred fifty-four million, twenty-six thousand, six hundred forty-three".
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