Base | Representation |
---|---|
bin | 10011010000010101100… |
… | …101101100011011010000 |
3 | 11200111102221001211110200 |
4 | 103100111211230123100 |
5 | 133134414301130000 |
6 | 2451513020055200 |
7 | 164412300345645 |
oct | 23202545543320 |
9 | 4614387054420 |
10 | 1323212130000 |
11 | 47019782a002 |
12 | 194545094500 |
13 | 97a170c9ac7 |
14 | 480882d5dcc |
15 | 24646b88500 |
hex | 1341596c6d0 |
1323212130000 has 300 divisors, whose sum is σ = 4752542502708. Its totient is φ = 343319040000.
The previous prime is 1323212129947. The next prime is 1323212130013. The reversal of 1323212130000 is 312123231.
1323212130000 is a `hidden beast` number, since 1 + 323 + 21 + 21 + 300 + 0 + 0 = 666.
It can be written as a sum of positive squares in 10 ways, for example, as 1151080077456 + 172132052544 = 1072884^2 + 414888^2 .
It is a tau number, because it is divible by the number of its divisors (300).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 3131320 + ... + 3528680.
Almost surely, 21323212130000 is an apocalyptic number.
1323212130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1323212130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2376271251354).
1323212130000 is an abundant number, since it is smaller than the sum of its proper divisors (3429330372708).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1323212130000 is a wasteful number, since it uses less digits than its factorization.
1323212130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 397432 (or 397408 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 1323212130000 its reverse (312123231), we get a palindrome (1323524253231).
The spelling of 1323212130000 in words is "one trillion, three hundred twenty-three billion, two hundred twelve million, one hundred thirty thousand".
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