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132323121041 is a prime number
BaseRepresentation
bin111101100111100010…
…0101001011110010001
3110122112211022000120212
41323033010221132101
54131444204333131
6140442143413505
712363042653666
oct1731704513621
9418484260525
10132323121041
1151132a52381
122178a8b4295
13c62a283877
146593c35a6d
153696ca0a2b
hex1ecf129791

132323121041 has 2 divisors, whose sum is σ = 132323121042. Its totient is φ = 132323121040.

The previous prime is 132323121037. The next prime is 132323121043. The reversal of 132323121041 is 140121323231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113245710400 + 19077410641 = 336520^2 + 138121^2 .

It is a cyclic number.

It is not a de Polignac number, because 132323121041 - 22 = 132323121037 is a prime.

It is a super-2 number, since 2×1323231210412 (a number of 23 digits) contains 22 as substring.

Together with 132323121043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132323120998 and 132323121016.

It is not a weakly prime, because it can be changed into another prime (132323121043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66161560520 + 66161560521.

It is an arithmetic number, because the mean of its divisors is an integer number (66161560521).

Almost surely, 2132323121041 is an apocalyptic number.

It is an amenable number.

132323121041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132323121041 is an equidigital number, since it uses as much as digits as its factorization.

132323121041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 132323121041 its reverse (140121323231), we get a palindrome (272444444272).

The spelling of 132323121041 in words is "one hundred thirty-two billion, three hundred twenty-three million, one hundred twenty-one thousand, forty-one".