Base | Representation |
---|---|
bin | 10011010000010110111… |
… | …001111110100001100111 |
3 | 11200111111110122100001112 |
4 | 103100112321332201213 |
5 | 133134440430133411 |
6 | 2451515125415235 |
7 | 164412656216423 |
oct | 23202671764147 |
9 | 4614443570045 |
10 | 1323234224231 |
11 | 4701a924a7a7 |
12 | 19455056a51b |
13 | 97a1b86450a |
14 | 4808b207b83 |
15 | 24648a9eb8b |
hex | 13416e7e867 |
1323234224231 has 2 divisors, whose sum is σ = 1323234224232. Its totient is φ = 1323234224230.
The previous prime is 1323234224189. The next prime is 1323234224233. The reversal of 1323234224231 is 1324224323231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1323234224231 - 26 = 1323234224167 is a prime.
It is a super-2 number, since 2×13232342242312 (a number of 25 digits) contains 22 as substring.
Together with 1323234224233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323234224233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661617112115 + 661617112116.
It is an arithmetic number, because the mean of its divisors is an integer number (661617112116).
Almost surely, 21323234224231 is an apocalyptic number.
1323234224231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323234224231 is an equidigital number, since it uses as much as digits as its factorization.
1323234224231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41472, while the sum is 32.
Adding to 1323234224231 its reverse (1324224323231), we get a palindrome (2647458547462).
The spelling of 1323234224231 in words is "one trillion, three hundred twenty-three billion, two hundred thirty-four million, two hundred twenty-four thousand, two hundred thirty-one".
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