Base | Representation |
---|---|
bin | 11000101001011011… |
… | …10000010001100111 |
3 | 1021011012011121210001 |
4 | 30110231300101213 |
5 | 204100001043143 |
6 | 10025013042131 |
7 | 645624613336 |
oct | 142455602147 |
9 | 37135147701 |
10 | 13232440423 |
11 | 5680405384 |
12 | 2693626347 |
13 | 132b5a6a07 |
14 | 8d7593d1d |
15 | 526a6814d |
hex | 314b70467 |
13232440423 has 4 divisors (see below), whose sum is σ = 13243938048. Its totient is φ = 13220942800.
The previous prime is 13232440393. The next prime is 13232440469. The reversal of 13232440423 is 32404423231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32404423231 = 17 ⋅1906142543.
It is a cyclic number.
It is not a de Polignac number, because 13232440423 - 29 = 13232439911 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13232440391 and 13232440400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13232440483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5747086 + ... + 5749387.
It is an arithmetic number, because the mean of its divisors is an integer number (3310984512).
Almost surely, 213232440423 is an apocalyptic number.
13232440423 is a deficient number, since it is larger than the sum of its proper divisors (11497625).
13232440423 is a wasteful number, since it uses less digits than its factorization.
13232440423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11497624.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 13232440423 its reverse (32404423231), we get a palindrome (45636863654).
The spelling of 13232440423 in words is "thirteen billion, two hundred thirty-two million, four hundred forty thousand, four hundred twenty-three".
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