Base | Representation |
---|---|
bin | 111101100111101111… |
… | …1101010000000001111 |
3 | 110122120022121201121101 |
4 | 1323033133222000033 |
5 | 4132003012413403 |
6 | 140442555243531 |
7 | 12363160102402 |
oct | 1731737520017 |
9 | 418508551541 |
10 | 132330201103 |
11 | 51136a48771 |
12 | 217911495a7 |
13 | c62b892359 |
14 | 6594b59d39 |
15 | 36976ed71d |
hex | 1ecf7ea00f |
132330201103 has 2 divisors, whose sum is σ = 132330201104. Its totient is φ = 132330201102.
The previous prime is 132330201089. The next prime is 132330201119. The reversal of 132330201103 is 301102033231.
It is a weak prime.
It is an emirp because it is prime and its reverse (301102033231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132330201103 - 217 = 132330070031 is a prime.
It is a super-2 number, since 2×1323302011032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132330801103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66165100551 + 66165100552.
It is an arithmetic number, because the mean of its divisors is an integer number (66165100552).
Almost surely, 2132330201103 is an apocalyptic number.
132330201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
132330201103 is an equidigital number, since it uses as much as digits as its factorization.
132330201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 132330201103 its reverse (301102033231), we get a palindrome (433432234334).
The spelling of 132330201103 in words is "one hundred thirty-two billion, three hundred thirty million, two hundred one thousand, one hundred three".
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