13233031204041 has 48 divisors (see below), whose sum is σ = 21572864089920. Its totient is φ = 7742828016000.

The previous prime is 13233031203989. The next prime is 13233031204123. The reversal of 13233031204041 is 14040213033231.

It is a happy number.

13233031204041 is a `hidden beast` number, since 1 + 3 + 233 + 0 + 3 + 1 + 20 + 404 + 1 = 666.

It is not a de Polignac number, because 13233031204041 - 2²⁹ = 13232494333129 is a prime.

It is a super-2 number, since 2×13233031204041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13233031203996 and 13233031204014.

It is not an unprimeable number, because it can be changed into a prime (13233031204541) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 35821446 + ... + 36188976.

It is an arithmetic number, because the mean of its divisors is an integer number (449434668540).

Almost surely, 2^{13233031204041} is an apocalyptic number.

13233031204041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13233031204041 is a deficient number, since it is larger than the sum of its proper divisors (8339832885879).

13233031204041 is a wasteful number, since it uses less digits than its factorization.

13233031204041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 380118 (or 380115 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13233031204041 its reverse (14040213033231), we get a palindrome (27273244237272).

The spelling of 13233031204041 in words is "thirteen trillion, two hundred thirty-three billion, thirty-one million, two hundred four thousand, forty-one".