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13233101412 = 2231102758451
BaseRepresentation
bin11000101001100000…
…10001101001100100
31021011020102012111010
430110300101221210
5204100133221122
610025035142220
7645633335406
oct142460215144
937136365433
1013233101412
115680816a53
1226938a4970
13132b77882b
148d76c6b76
15526b48e0c
hex314c11a64

13233101412 has 12 divisors (see below), whose sum is σ = 30877236656. Its totient is φ = 4411033800.

The previous prime is 13233101407. The next prime is 13233101443. The reversal of 13233101412 is 21410133231.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×132331014122 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551379214 + ... + 551379237.

Almost surely, 213233101412 is an apocalyptic number.

13233101412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13233101412 is an abundant number, since it is smaller than the sum of its proper divisors (17644135244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13233101412 is a wasteful number, since it uses less digits than its factorization.

13233101412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1102758458 (or 1102758456 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13233101412 its reverse (21410133231), we get a palindrome (34643234643).

The spelling of 13233101412 in words is "thirteen billion, two hundred thirty-three million, one hundred one thousand, four hundred twelve".

Divisors: 1 2 3 4 6 12 1102758451 2205516902 3308275353 4411033804 6616550706 13233101412