Base | Representation |
---|---|
bin | 111101100111110001… |
… | …0110001111101100011 |
3 | 110122120101011100002202 |
4 | 1323033202301331203 |
5 | 4132003220121011 |
6 | 140443025003415 |
7 | 12363200053262 |
oct | 1731742617543 |
9 | 418511140082 |
10 | 132331020131 |
11 | 51137458052 |
12 | 2179148356b |
13 | c62babb09b |
14 | 6594cd05d9 |
15 | 369781123b |
hex | 1ecf8b1f63 |
132331020131 has 2 divisors, whose sum is σ = 132331020132. Its totient is φ = 132331020130.
The previous prime is 132331020113. The next prime is 132331020139. The reversal of 132331020131 is 131020133231.
Together with previous prime (132331020113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132331020131 is a prime.
It is a super-2 number, since 2×1323310201312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132331020139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66165510065 + 66165510066.
It is an arithmetic number, because the mean of its divisors is an integer number (66165510066).
Almost surely, 2132331020131 is an apocalyptic number.
132331020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
132331020131 is an equidigital number, since it uses as much as digits as its factorization.
132331020131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 132331020131 its reverse (131020133231), we get a palindrome (263351153362).
The spelling of 132331020131 in words is "one hundred thirty-two billion, three hundred thirty-one million, twenty thousand, one hundred thirty-one".
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