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132331401340 = 2256616570067
BaseRepresentation
bin111101100111110010…
…0001111000001111100
3110122120101212201000121
41323033210033001330
54132003314320330
6140443041104324
712363203231545
oct1731744170174
9418511781017
10132331401340
11511376984a6
12217916280a4
13c62bbc2758
146594d8d4cc
15369788917a
hex1ecf90f07c

132331401340 has 12 divisors (see below), whose sum is σ = 277895942856. Its totient is φ = 52932560528.

The previous prime is 132331401317. The next prime is 132331401341. The reversal of 132331401340 is 43104133231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132331401341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3308285014 + ... + 3308285053.

It is an arithmetic number, because the mean of its divisors is an integer number (23157995238).

Almost surely, 2132331401340 is an apocalyptic number.

132331401340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132331401340 is an abundant number, since it is smaller than the sum of its proper divisors (145564541516).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132331401340 is a wasteful number, since it uses less digits than its factorization.

132331401340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6616570076 (or 6616570074 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 132331401340 its reverse (43104133231), we get a palindrome (175435534571).

The spelling of 132331401340 in words is "one hundred thirty-two billion, three hundred thirty-one million, four hundred one thousand, three hundred forty".

Divisors: 1 2 4 5 10 20 6616570067 13233140134 26466280268 33082850335 66165700670 132331401340