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132332001330000 = 243545839755449
BaseRepresentation
bin11110000101101011110001…
…111011101000001101010000
3122100112211000200221011111110
4132011223301323220031100
5114321111414320030000
61145240252051413320
736605446233022323
oct3605536173501520
9570484020834443
10132332001330000
113918a76095417a
1212a129b35b4240
1358abb14831a84
142496c8dd1c7ba
1510473d43d5850
hex785af1ee8350

132332001330000 has 200 divisors, whose sum is σ = 427259070832000. Its totient is φ = 35282443392000.

The previous prime is 132332001329971. The next prime is 132332001330041. The reversal of 132332001330000 is 33100233231.

132332001330000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (200).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 174792276 + ... + 175547724.

It is an arithmetic number, because the mean of its divisors is an integer number (2136295354160).

Almost surely, 2132332001330000 is an apocalyptic number.

132332001330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132332001330000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (213629535416000).

132332001330000 is an abundant number, since it is smaller than the sum of its proper divisors (294927069502000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132332001330000 is an equidigital number, since it uses as much as digits as its factorization.

132332001330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 761319 (or 761298 counting only the distinct ones).

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 132332001330000 its reverse (33100233231), we get a palindrome (132365101563231).

The spelling of 132332001330000 in words is "one hundred thirty-two trillion, three hundred thirty-two billion, one million, three hundred thirty thousand".