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132340105535399 is a prime number
BaseRepresentation
bin11110000101110011010100…
…111110101101111110100111
3122100120120221111102110022222
4132011303110332231332213
5114321230014004113044
61145244112152542555
736606154120441316
oct3605632476557647
9570516844373288
10132340105535399
113919313a525693
1212a144956b1a5b
1358ac80682b898
14249741c39027d
15104770ab168ee
hex785cd4fadfa7

132340105535399 has 2 divisors, whose sum is σ = 132340105535400. Its totient is φ = 132340105535398.

The previous prime is 132340105535293. The next prime is 132340105535401. The reversal of 132340105535399 is 993535501043231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132340105535399 is a prime.

It is a Sophie Germain prime.

Together with 132340105535401, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132340105535399.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132340105535699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170052767699 + 66170052767700.

It is an arithmetic number, because the mean of its divisors is an integer number (66170052767700).

Almost surely, 2132340105535399 is an apocalyptic number.

132340105535399 is a deficient number, since it is larger than the sum of its proper divisors (1).

132340105535399 is an equidigital number, since it uses as much as digits as its factorization.

132340105535399 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6561000, while the sum is 53.

The spelling of 132340105535399 in words is "one hundred thirty-two trillion, three hundred forty billion, one hundred five million, five hundred thirty-five thousand, three hundred ninety-nine".