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132400211433 = 376304771973
BaseRepresentation
bin111101101001110101…
…0101110010111101001
3110122202012100121201120
41323103222232113221
54132123423231213
6140453540005453
712365000141220
oct1732352562751
9418665317646
10132400211433
1151172516546
12217b0690889
13c640235799
1465a0181cb7
15369d92c423
hex1ed3aae5e9

132400211433 has 8 divisors (see below), whose sum is σ = 201752703168. Its totient is φ = 75657263664.

The previous prime is 132400211417. The next prime is 132400211443. The reversal of 132400211433 is 334112004231.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132400211433 - 24 = 132400211417 is a prime.

It is not an unprimeable number, because it can be changed into a prime (132400211443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3152385966 + ... + 3152386007.

It is an arithmetic number, because the mean of its divisors is an integer number (25219087896).

Almost surely, 2132400211433 is an apocalyptic number.

It is an amenable number.

132400211433 is a deficient number, since it is larger than the sum of its proper divisors (69352491735).

132400211433 is an equidigital number, since it uses as much as digits as its factorization.

132400211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6304771983.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 132400211433 its reverse (334112004231), we get a palindrome (466512215664).

The spelling of 132400211433 in words is "one hundred thirty-two billion, four hundred million, two hundred eleven thousand, four hundred thirty-three".

Divisors: 1 3 7 21 6304771973 18914315919 44133403811 132400211433