132403124130343 has 4 divisors (see below), whose sum is σ = 144439771778568. Its totient is φ = 120366476482120.

The previous prime is 132403124130311. The next prime is 132403124130349. The reversal of 132403124130343 is 343031421304231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132403124130343 - 2⁵ = 132403124130311 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132403124130299 and 132403124130308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132403124130349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6018323824096 + ... + 6018323824117.

It is an arithmetic number, because the mean of its divisors is an integer number (36109942944642).

Almost surely, 2^{132403124130343} is an apocalyptic number.

132403124130343 is a deficient number, since it is larger than the sum of its proper divisors (12036647648225).

132403124130343 is a wasteful number, since it uses less digits than its factorization.

132403124130343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12036647648224.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 132403124130343 its reverse (343031421304231), we get a palindrome (475434545434574).

The spelling of 132403124130343 in words is "one hundred thirty-two trillion, four hundred three billion, one hundred twenty-four million, one hundred thirty thousand, three hundred forty-three".