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132405002501503 is a prime number
BaseRepresentation
bin11110000110101111110001…
…001000111111110101111111
3122100210210110021111220201011
4132012233301020333311333
5114323310421120022003
61145334003552100051
736613642251524164
oct3606576110776577
9570723407456634
10132405002501503
1139208712136876
1212a24b87534627
1358b5979980c44
14249a61736406b
15104925821c46d
hex786bf123fd7f

132405002501503 has 2 divisors, whose sum is σ = 132405002501504. Its totient is φ = 132405002501502.

The previous prime is 132405002501501. The next prime is 132405002501599. The reversal of 132405002501503 is 305105200504231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132405002501503 - 21 = 132405002501501 is a prime.

Together with 132405002501501, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132405002501501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66202501250751 + 66202501250752.

It is an arithmetic number, because the mean of its divisors is an integer number (66202501250752).

Almost surely, 2132405002501503 is an apocalyptic number.

132405002501503 is a deficient number, since it is larger than the sum of its proper divisors (1).

132405002501503 is an equidigital number, since it uses as much as digits as its factorization.

132405002501503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 132405002501503 in words is "one hundred thirty-two trillion, four hundred five billion, two million, five hundred one thousand, five hundred three".