Base | Representation |
---|---|
bin | 1100000010101110101110… |
… | …0010111100100111000111 |
3 | 1201212211102220200200220111 |
4 | 3000223223202330213013 |
5 | 3213420122444410231 |
6 | 44054503354013451 |
7 | 2534430224405155 |
oct | 300535342744707 |
9 | 51784386620814 |
10 | 13241041013191 |
11 | 4245548505612 |
12 | 159a251a17287 |
13 | 750817926a84 |
14 | 33ac26a5a3d5 |
15 | 17e66abc64b1 |
hex | c0aeb8bc9c7 |
13241041013191 has 2 divisors, whose sum is σ = 13241041013192. Its totient is φ = 13241041013190.
The previous prime is 13241041013129. The next prime is 13241041013209. The reversal of 13241041013191 is 19131014014231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13241041013191 - 229 = 13240504142279 is a prime.
It is a super-2 number, since 2×132410410131912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13241041013111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620520506595 + 6620520506596.
It is an arithmetic number, because the mean of its divisors is an integer number (6620520506596).
Almost surely, 213241041013191 is an apocalyptic number.
13241041013191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241041013191 is an equidigital number, since it uses as much as digits as its factorization.
13241041013191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 13241041013191 in words is "thirteen trillion, two hundred forty-one billion, forty-one million, thirteen thousand, one hundred ninety-one".
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