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13241053305655 = 572627831439651
BaseRepresentation
bin1100000010101110110001…
…0001110101101100110111
31201212211110202211012222221
43000223230101311230313
53213420134121240110
644054504513303211
72534430434033230
oct300535421655467
951784422735887
1013241053305655
11424555444107a
12159a255b64b07
1375081a33bc16
1433ac2853a087
1517e66bd037da
hexc0aec475b37

13241053305655 has 16 divisors (see below), whose sum is σ = 18159240536064. Its totient is φ = 9079538551200.

The previous prime is 13241053305617. The next prime is 13241053305661. The reversal of 13241053305655 is 55650335014231.

It is a de Polignac number, because none of the positive numbers 2k-13241053305655 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8477580 + ... + 9917230.

It is an arithmetic number, because the mean of its divisors is an integer number (1134952533504).

Almost surely, 213241053305655 is an apocalyptic number.

13241053305655 is a deficient number, since it is larger than the sum of its proper divisors (4918187230409).

13241053305655 is a wasteful number, since it uses less digits than its factorization.

13241053305655 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1702446.

The product of its (nonzero) digits is 810000, while the sum is 43.

Adding to 13241053305655 its reverse (55650335014231), we get a palindrome (68891388319886).

The spelling of 13241053305655 in words is "thirteen trillion, two hundred forty-one billion, fifty-three million, three hundred five thousand, six hundred fifty-five".

Divisors: 1 5 7 35 262783 1313915 1439651 1839481 7198255 9197405 10077557 50387785 378315808733 1891579043665 2648210661131 13241053305655