132413296875581 has 2 divisors, whose sum is σ = 132413296875582. Its totient is φ = 132413296875580.

The previous prime is 132413296875529. The next prime is 132413296875583. The reversal of 132413296875581 is 185578692314231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127953787695556 + 4459509180025 = 11311666^2 + 2111755^2 .

It is a cyclic number.

It is not a de Polignac number, because 132413296875581 - 2¹⁰ = 132413296874557 is a prime.

It is a super-2 number, since 2×132413296875581² (a number of 29 digits) contains 22 as substring.

Together with 132413296875583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132413296875583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66206648437790 + 66206648437791.

It is an arithmetic number, because the mean of its divisors is an integer number (66206648437791).

Almost surely, 2^{132413296875581} is an apocalyptic number.

It is an amenable number.

132413296875581 is a deficient number, since it is larger than the sum of its proper divisors (1).

132413296875581 is an equidigital number, since it uses as much as digits as its factorization.

132413296875581 is an evil number, because the sum of its binary digits is even.

The product of its digits is 87091200, while the sum is 65.

The spelling of 132413296875581 in words is "one hundred thirty-two trillion, four hundred thirteen billion, two hundred ninety-six million, eight hundred seventy-five thousand, five hundred eighty-one".