Search a number
-
+
132414032753 is a prime number
BaseRepresentation
bin111101101010001111…
…1011100101101110001
3110122210011100211000022
41323110133130231301
54132140443022003
6140455152133225
712365225464502
oct1732437345561
9418704324008
10132414032753
115117a2a6722
12217b5237215
13c643064792
1465a1d3cba9
15369ec5c738
hex1ed47dcb71

132414032753 has 2 divisors, whose sum is σ = 132414032754. Its totient is φ = 132414032752.

The previous prime is 132414032747. The next prime is 132414032759. The reversal of 132414032753 is 357230414231.

It is a balanced prime because it is at equal distance from previous prime (132414032747) and next prime (132414032759).

It can be written as a sum of positive squares in only one way, i.e., 109307600689 + 23106432064 = 330617^2 + 152008^2 .

It is a cyclic number.

It is not a de Polignac number, because 132414032753 - 26 = 132414032689 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (132414032759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66207016376 + 66207016377.

It is an arithmetic number, because the mean of its divisors is an integer number (66207016377).

Almost surely, 2132414032753 is an apocalyptic number.

It is an amenable number.

132414032753 is a deficient number, since it is larger than the sum of its proper divisors (1).

132414032753 is an equidigital number, since it uses as much as digits as its factorization.

132414032753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 132414032753 its reverse (357230414231), we get a palindrome (489644446984).

The spelling of 132414032753 in words is "one hundred thirty-two billion, four hundred fourteen million, thirty-two thousand, seven hundred fifty-three".