Base | Representation |
---|---|
bin | 11110000110111110000100… |
… | …110111011001010000000000 |
3 | 122100212021002222022012100000 |
4 | 132012332010313121100000 |
5 | 114324033402122114312 |
6 | 1145345024245200000 |
7 | 36615025052536032 |
oct | 3606760467312000 |
9 | 570767088265300 |
10 | 132420365816832 |
11 | 39214186347a95 |
12 | 12a27b54700000 |
13 | 58b7257865a82 |
14 | 249b27391dc52 |
15 | 1049856d9aadc |
hex | 786f84dd9400 |
132420365816832 has 264 divisors, whose sum is σ = 417392066072800. Its totient is φ = 41816956133376.
The previous prime is 132420365816807. The next prime is 132420365816833. The reversal of 132420365816832 is 238618563024231.
132420365816832 is a `hidden beast` number, since 1 + 3 + 2 + 4 + 20 + 3 + 6 + 581 + 6 + 8 + 32 = 666.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132420365816833) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9276607 + ... + 18732222.
Almost surely, 2132420365816832 is an apocalyptic number.
132420365816832 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132420365816832 is an abundant number, since it is smaller than the sum of its proper divisors (284971700255968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132420365816832 is an equidigital number, since it uses as much as digits as its factorization.
132420365816832 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28008883 (or 28008853 counting only the distinct ones).
The product of its (nonzero) digits is 9953280, while the sum is 54.
The spelling of 132420365816832 in words is "one hundred thirty-two trillion, four hundred twenty billion, three hundred sixty-five million, eight hundred sixteen thousand, eight hundred thirty-two".
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