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132421151 is a prime number
BaseRepresentation
bin1111110010010…
…01011000011111
3100020011200200002
413321021120133
5232344434101
621050124515
73165363332
oct771113037
9306150602
10132421151
1168825a75
123842073b
1321585815
1413830619
15b95ad6b
hex7e4961f

132421151 has 2 divisors, whose sum is σ = 132421152. Its totient is φ = 132421150.

The previous prime is 132421141. The next prime is 132421153. The reversal of 132421151 is 151124231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132421151 - 26 = 132421087 is a prime.

It is a super-2 number, since 2×1324211512 = 35070722464329602, which contains 22 as substring.

Together with 132421153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132421153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66210575 + 66210576.

It is an arithmetic number, because the mean of its divisors is an integer number (66210576).

Almost surely, 2132421151 is an apocalyptic number.

132421151 is a deficient number, since it is larger than the sum of its proper divisors (1).

132421151 is an equidigital number, since it uses as much as digits as its factorization.

132421151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 240, while the sum is 20.

The square root of 132421151 is about 11507.4389418324. The cubic root of 132421151 is about 509.7052647908.

Adding to 132421151 its reverse (151124231), we get a palindrome (283545382).

The spelling of 132421151 in words is "one hundred thirty-two million, four hundred twenty-one thousand, one hundred fifty-one".