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13242153551 = 111203832141
BaseRepresentation
bin11000101010100101…
…10011101001001111
31021011212110002200112
430111102303221033
5204104442403201
610030001150235
7646103306444
oct142522635117
937155402615
1013242153551
115685939a60
12269692b37b
1313305c7b23
148d89a19cb
155278360bb
hex3154b3a4f

13242153551 has 4 divisors (see below), whose sum is σ = 14445985704. Its totient is φ = 12038321400.

The previous prime is 13242153479. The next prime is 13242153557. The reversal of 13242153551 is 15535124231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13242153551 - 222 = 13237959247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13242153557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601916060 + ... + 601916081.

It is an arithmetic number, because the mean of its divisors is an integer number (3611496426).

Almost surely, 213242153551 is an apocalyptic number.

13242153551 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13242153551 is a deficient number, since it is larger than the sum of its proper divisors (1203832153).

13242153551 is a wasteful number, since it uses less digits than its factorization.

13242153551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1203832152.

The product of its digits is 18000, while the sum is 32.

Adding to 13242153551 its reverse (15535124231), we get a palindrome (28777277782).

The spelling of 13242153551 in words is "thirteen billion, two hundred forty-two million, one hundred fifty-three thousand, five hundred fifty-one".

Divisors: 1 11 1203832141 13242153551