132425003525135 has 4 divisors (see below), whose sum is σ = 158910004230168. Its totient is φ = 105940002820104.

The previous prime is 132425003525039. The next prime is 132425003525209. The reversal of 132425003525135 is 531525300524231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132425003525135 - 2²² = 132424999330831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132425003525092 and 132425003525101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13242500352509 + ... + 13242500352518.

It is an arithmetic number, because the mean of its divisors is an integer number (39727501057542).

Almost surely, 2^{132425003525135} is an apocalyptic number.

132425003525135 is a deficient number, since it is larger than the sum of its proper divisors (26485000705033).

132425003525135 is an equidigital number, since it uses as much as digits as its factorization.

132425003525135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26485000705032.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 132425003525135 in words is "one hundred thirty-two trillion, four hundred twenty-five billion, three million, five hundred twenty-five thousand, one hundred thirty-five".