132430204120337 has 2 divisors, whose sum is σ = 132430204120338. Its totient is φ = 132430204120336.

The previous prime is 132430204120267. The next prime is 132430204120339. The reversal of 132430204120337 is 733021402034231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96265905087361 + 36164299032976 = 9811519^2 + 6013676^2 .

It is a cyclic number.

It is not a de Polignac number, because 132430204120337 - 2²² = 132430199926033 is a prime.

It is a super-3 number, since 3×132430204120337³ (a number of 43 digits) contains 333 as substring.

Together with 132430204120339, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132430204120297 and 132430204120306.

It is not a weakly prime, because it can be changed into another prime (132430204120339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66215102060168 + 66215102060169.

It is an arithmetic number, because the mean of its divisors is an integer number (66215102060169).

Almost surely, 2^{132430204120337} is an apocalyptic number.

It is an amenable number.

132430204120337 is a deficient number, since it is larger than the sum of its proper divisors (1).

132430204120337 is an equidigital number, since it uses as much as digits as its factorization.

132430204120337 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 35.

Adding to 132430204120337 its reverse (733021402034231), we get a palindrome (865451606154568).

The spelling of 132430204120337 in words is "one hundred thirty-two trillion, four hundred thirty billion, two hundred four million, one hundred twenty thousand, three hundred thirty-seven".