Base | Representation |
---|---|
bin | 11000101010101100… |
… | …11101111010110111 |
3 | 1021011221020211222222 |
4 | 30111112131322313 |
5 | 204110214110033 |
6 | 10030033512555 |
7 | 646114414211 |
oct | 142526357267 |
9 | 37157224888 |
10 | 13243113143 |
11 | 5686434a07 |
12 | 269711275b |
13 | 1330872830 |
14 | 8d8b715b1 |
15 | 527975598 |
hex | 31559deb7 |
13243113143 has 4 divisors (see below), whose sum is σ = 14261814168. Its totient is φ = 12224412120.
The previous prime is 13243113137. The next prime is 13243113179. The reversal of 13243113143 is 34131134231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13243113143 - 28 = 13243112887 is a prime.
It is a super-3 number, since 3×132431131433 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13243113133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509350493 + ... + 509350518.
It is an arithmetic number, because the mean of its divisors is an integer number (3565453542).
Almost surely, 213243113143 is an apocalyptic number.
13243113143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13243113143 is a deficient number, since it is larger than the sum of its proper divisors (1018701025).
13243113143 is a wasteful number, since it uses less digits than its factorization.
13243113143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1018701024.
The product of its digits is 2592, while the sum is 26.
Adding to 13243113143 its reverse (34131134231), we get a palindrome (47374247374).
The spelling of 13243113143 in words is "thirteen billion, two hundred forty-three million, one hundred thirteen thousand, one hundred forty-three".
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