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13243311143 = 45728978799
BaseRepresentation
bin11000101010101110…
…01110010000100111
31021011221121220121022
430111113032100213
5204110241424033
610030042041355
7646116200366
oct142527162047
937157556538
1013243311143
11568655a747
1226971a925b
1313309119aa
148d8bc37dd
155279b4098
hex3155ce427

13243311143 has 4 divisors (see below), whose sum is σ = 13272290400. Its totient is φ = 13214331888.

The previous prime is 13243311131. The next prime is 13243311181. The reversal of 13243311143 is 34111334231.

13243311143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13243311143 - 26 = 13243311079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13243311113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14488943 + ... + 14489856.

It is an arithmetic number, because the mean of its divisors is an integer number (3318072600).

Almost surely, 213243311143 is an apocalyptic number.

13243311143 is a deficient number, since it is larger than the sum of its proper divisors (28979257).

13243311143 is an equidigital number, since it uses as much as digits as its factorization.

13243311143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28979256.

The product of its digits is 2592, while the sum is 26.

Adding to 13243311143 its reverse (34111334231), we get a palindrome (47354645374).

The spelling of 13243311143 in words is "thirteen billion, two hundred forty-three million, three hundred eleven thousand, one hundred forty-three".

Divisors: 1 457 28978799 13243311143