Base | Representation |
---|---|
bin | 111101101010110100… |
… | …1000100111101111111 |
3 | 110122211111200102112121 |
4 | 1323111221010331333 |
5 | 4132210413143033 |
6 | 140501121543411 |
7 | 12365551523665 |
oct | 1732551047577 |
9 | 418744612477 |
10 | 132433334143 |
11 | 5118a18a090 |
12 | 217bb7a4b67 |
13 | c647061c16 |
14 | 65a4724c35 |
15 | 36a17c162d |
hex | 1ed5a44f7f |
132433334143 has 4 divisors (see below), whose sum is σ = 144472728168. Its totient is φ = 120393940120.
The previous prime is 132433334141. The next prime is 132433334149. The reversal of 132433334143 is 341433334231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132433334143 - 21 = 132433334141 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132433334099 and 132433334108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132433334141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6019696996 + ... + 6019697017.
It is an arithmetic number, because the mean of its divisors is an integer number (36118182042).
Almost surely, 2132433334143 is an apocalyptic number.
132433334143 is a deficient number, since it is larger than the sum of its proper divisors (12039394025).
132433334143 is a wasteful number, since it uses less digits than its factorization.
132433334143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12039394024.
The product of its digits is 93312, while the sum is 34.
Adding to 132433334143 its reverse (341433334231), we get a palindrome (473866668374).
The spelling of 132433334143 in words is "one hundred thirty-two billion, four hundred thirty-three million, three hundred thirty-four thousand, one hundred forty-three".
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