Base | Representation |
---|---|
bin | 1100000010111000001011… |
… | …1000111011101101011111 |
3 | 1201220001222212111111222122 |
4 | 3000232002320323231133 |
5 | 3213440323003330122 |
6 | 44100003340133155 |
7 | 2534550155530334 |
oct | 300560270735537 |
9 | 51801885444878 |
10 | 13243580136287 |
11 | 4246630800356 |
12 | 159a8402371bb |
13 | 750b309a3887 |
14 | 33adc7d7298b |
15 | 17e768a7e142 |
hex | c0b82e3bb5f |
13243580136287 has 4 divisors (see below), whose sum is σ = 13332463224600. Its totient is φ = 13154697047976.
The previous prime is 13243580136257. The next prime is 13243580136313. The reversal of 13243580136287 is 78263108534231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13243580136287 - 240 = 12144068508511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13243580136217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44441543933 + ... + 44441544230.
It is an arithmetic number, because the mean of its divisors is an integer number (3333115806150).
Almost surely, 213243580136287 is an apocalyptic number.
13243580136287 is a deficient number, since it is larger than the sum of its proper divisors (88883088313).
13243580136287 is an equidigital number, since it uses as much as digits as its factorization.
13243580136287 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88883088312.
The product of its (nonzero) digits is 5806080, while the sum is 53.
The spelling of 13243580136287 in words is "thirteen trillion, two hundred forty-three billion, five hundred eighty million, one hundred thirty-six thousand, two hundred eighty-seven".
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