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132440426133 = 344146808711
BaseRepresentation
bin111101101011000010…
…0001000011010010101
3110122212000000201220220
41323112010020122111
54132214222114013
6140501533544553
712365666022231
oct1732604103225
9418760021826
10132440426133
1151193193434
1221802045159
13c648675c72
1465a564d5c1
1536a2222b23
hex1ed6108695

132440426133 has 4 divisors (see below), whose sum is σ = 176587234848. Its totient is φ = 88293617420.

The previous prime is 132440426099. The next prime is 132440426137. The reversal of 132440426133 is 331624044231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132440426133 - 229 = 131903555221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132440426094 and 132440426103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132440426137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22073404353 + ... + 22073404358.

It is an arithmetic number, because the mean of its divisors is an integer number (44146808712).

Almost surely, 2132440426133 is an apocalyptic number.

It is an amenable number.

132440426133 is a deficient number, since it is larger than the sum of its proper divisors (44146808715).

132440426133 is an equidigital number, since it uses as much as digits as its factorization.

132440426133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44146808714.

The product of its (nonzero) digits is 41472, while the sum is 33.

The spelling of 132440426133 in words is "one hundred thirty-two billion, four hundred forty million, four hundred twenty-six thousand, one hundred thirty-three".

Divisors: 1 3 44146808711 132440426133