Base | Representation |
---|---|
bin | 1100000010111010000111… |
… | …1000101000110010000111 |
3 | 1201220010100010000002001201 |
4 | 3000232201320220302013 |
5 | 3213442404114334310 |
6 | 44100131114003331 |
7 | 2534566101561424 |
oct | 300564170506207 |
9 | 51803303002051 |
10 | 13244100152455 |
11 | 4246878299187 |
12 | 159a966416547 |
13 | 750bb4646553 |
14 | 33b037058d4b |
15 | 17e79954ce3a |
hex | c0ba1e28c87 |
13244100152455 has 4 divisors (see below), whose sum is σ = 15892920182952. Its totient is φ = 10595280121960.
The previous prime is 13244100152449. The next prime is 13244100152477. The reversal of 13244100152455 is 55425100144231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13244100152455 - 23 = 13244100152447 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1324410015241 + ... + 1324410015250.
It is an arithmetic number, because the mean of its divisors is an integer number (3973230045738).
Almost surely, 213244100152455 is an apocalyptic number.
13244100152455 is a deficient number, since it is larger than the sum of its proper divisors (2648820030497).
13244100152455 is an equidigital number, since it uses as much as digits as its factorization.
13244100152455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2648820030496.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 13244100152455 its reverse (55425100144231), we get a palindrome (68669200296686).
The spelling of 13244100152455 in words is "thirteen trillion, two hundred forty-four billion, one hundred million, one hundred fifty-two thousand, four hundred fifty-five".
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