132441005533 has 4 divisors (see below), whose sum is σ = 132522710428. Its totient is φ = 132359300640.

The previous prime is 132441005491. The next prime is 132441005537. The reversal of 132441005533 is 335500144231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 108713300089 + 23727705444 = 329717^2 + 154038^2 .

It is a cyclic number.

It is not a de Polignac number, because 132441005533 - 2¹³ = 132440997341 is a prime.

It is a super-2 number, since 2×132441005533² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132441005495 and 132441005504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132441005537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40850016 + ... + 40853257.

It is an arithmetic number, because the mean of its divisors is an integer number (33130677607).

Almost surely, 2^132441005533 is an apocalyptic number.

It is an amenable number.

132441005533 is a deficient number, since it is larger than the sum of its proper divisors (81704895).

132441005533 is an equidigital number, since it uses as much as digits as its factorization.

132441005533 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81704894.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 132441005533 its reverse (335500144231), we get a palindrome (467941149764).

The spelling of 132441005533 in words is "one hundred thirty-two billion, four hundred forty-one million, five thousand, five hundred thirty-three".