Base | Representation |
---|---|
bin | 10011010001011110110… |
… | …010011100111100011111 |
3 | 11200121121111220211012201 |
4 | 103101132302130330133 |
5 | 133144423143224411 |
6 | 2452234530112331 |
7 | 164454602021464 |
oct | 23213662347437 |
9 | 4617544824181 |
10 | 1324440211231 |
11 | 470767a75675 |
12 | 19482841b6a7 |
13 | 97b81673aa7 |
14 | 4816345566b |
15 | 246b98be3c1 |
hex | 1345ec9cf1f |
1324440211231 has 2 divisors, whose sum is σ = 1324440211232. Its totient is φ = 1324440211230.
The previous prime is 1324440211217. The next prime is 1324440211327. The reversal of 1324440211231 is 1321120444231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1324440211231 - 225 = 1324406656799 is a prime.
It is a super-2 number, since 2×13244402112312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1324440211231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324440211931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662220105615 + 662220105616.
It is an arithmetic number, because the mean of its divisors is an integer number (662220105616).
Almost surely, 21324440211231 is an apocalyptic number.
1324440211231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324440211231 is an equidigital number, since it uses as much as digits as its factorization.
1324440211231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1324440211231 its reverse (1321120444231), we get a palindrome (2645560655462).
The spelling of 1324440211231 in words is "one trillion, three hundred twenty-four billion, four hundred forty million, two hundred eleven thousand, two hundred thirty-one".
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