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132455207 is a prime number
BaseRepresentation
bin1111110010100…
…01101100100111
3100020020102101102
413321101230213
5232402031312
621050550315
73165564533
oct771215447
9306212342
10132455207
1168849615
123843839b
1321598181
141383cbc3
15b965ec2
hex7e51b27

132455207 has 2 divisors, whose sum is σ = 132455208. Its totient is φ = 132455206.

The previous prime is 132455171. The next prime is 132455221. The reversal of 132455207 is 702554231.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (702554231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132455207 - 28 = 132454951 is a prime.

It is a super-2 number, since 2×1324552072 = 35088763722825698, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132455207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132455107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66227603 + 66227604.

It is an arithmetic number, because the mean of its divisors is an integer number (66227604).

Almost surely, 2132455207 is an apocalyptic number.

132455207 is a deficient number, since it is larger than the sum of its proper divisors (1).

132455207 is an equidigital number, since it uses as much as digits as its factorization.

132455207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8400, while the sum is 29.

The square root of 132455207 is about 11508.9185851669. The cubic root of 132455207 is about 509.7489562870.

The spelling of 132455207 in words is "one hundred thirty-two million, four hundred fifty-five thousand, two hundred seven".