Base | Representation |
---|---|
bin | 11110000111100000100110… |
… | …101111101110111111110101 |
3 | 122100222210210211122211002101 |
4 | 132013200212233232333311 |
5 | 114330140320003043432 |
6 | 1145414035240542101 |
7 | 36620506610345611 |
oct | 3607404657567765 |
9 | 570883724584071 |
10 | 132457441456117 |
11 | 392289815a8598 |
12 | 12a33181181931 |
13 | 58ba8b5ac837b |
14 | 249cd8d974341 |
15 | 104a7c6c804e7 |
hex | 787826beeff5 |
132457441456117 has 12 divisors (see below), whose sum is σ = 142807496164960. Its totient is φ = 122805143246016.
The previous prime is 132457441456111. The next prime is 132457441456147. The reversal of 132457441456117 is 711654144754231.
It is not a de Polignac number, because 132457441456117 - 211 = 132457441454069 is a prime.
It is a super-3 number, since 3×1324574414561173 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132457441456111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3420355617 + ... + 3420394342.
Almost surely, 2132457441456117 is an apocalyptic number.
132457441456117 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
132457441456117 is a deficient number, since it is larger than the sum of its proper divisors (10350054708843).
132457441456117 is an equidigital number, since it uses as much as digits as its factorization.
132457441456117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6840750060 (or 6840750043 counting only the distinct ones).
The product of its digits is 11289600, while the sum is 55.
The spelling of 132457441456117 in words is "one hundred thirty-two trillion, four hundred fifty-seven billion, four hundred forty-one million, four hundred fifty-six thousand, one hundred seventeen".
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