13246114033 has 2 divisors, whose sum is σ = 13246114034. Its totient is φ = 13246114032.

The previous prime is 13246114003. The next prime is 13246114061. The reversal of 13246114033 is 33041164231.

13246114033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (13246114061) can be obtained adding 13246114033 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11395135504 + 1850978529 = 106748^2 + 43023^2 .

It is an emirp because it is prime and its reverse (33041164231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13246114033 - 2¹⁷ = 13245982961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13246113992 and 13246114010.

It is not a weakly prime, because it can be changed into another prime (13246114003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6623057016 + 6623057017.

It is an arithmetic number, because the mean of its divisors is an integer number (6623057017).

Almost surely, 2^13246114033 is an apocalyptic number.

It is an amenable number.

13246114033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13246114033 is an equidigital number, since it uses as much as digits as its factorization.

13246114033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13246114033 its reverse (33041164231), we get a palindrome (46287278264).

The spelling of 13246114033 in words is "thirteen billion, two hundred forty-six million, one hundred fourteen thousand, thirty-three".