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1325105100073 is a prime number
BaseRepresentation
bin10011010010000110011…
…010110011010100101001
311200200022212000200020101
4103102012122303110221
5133202303401200243
62452424521025401
7164510224336066
oct23220632632451
94620285020211
101325105100073
11470a79313487
12194993025261
1397c5933b941
14481c788dc6d
1524707e5854d
hex134866b3529

1325105100073 has 2 divisors, whose sum is σ = 1325105100074. Its totient is φ = 1325105100072.

The previous prime is 1325105100013. The next prime is 1325105100133. The reversal of 1325105100073 is 3700015015231.

It is a balanced prime because it is at equal distance from previous prime (1325105100013) and next prime (1325105100133).

It can be written as a sum of positive squares in only one way, i.e., 842424758569 + 482680341504 = 917837^2 + 694752^2 .

It is an emirp because it is prime and its reverse (3700015015231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1325105100073 - 29 = 1325105099561 is a prime.

It is not a weakly prime, because it can be changed into another prime (1325105100013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662552550036 + 662552550037.

It is an arithmetic number, because the mean of its divisors is an integer number (662552550037).

Almost surely, 21325105100073 is an apocalyptic number.

It is an amenable number.

1325105100073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325105100073 is an equidigital number, since it uses as much as digits as its factorization.

1325105100073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3150, while the sum is 28.

The spelling of 1325105100073 in words is "one trillion, three hundred twenty-five billion, one hundred five million, one hundred thousand, seventy-three".