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1325105100133 is a prime number
BaseRepresentation
bin10011010010000110011…
…010110011010101100101
311200200022212000200022121
4103102012122303111211
5133202303401201013
62452424521025541
7164510224336213
oct23220632632545
94620285020277
101325105100133
11470a79313531
121949930252b1
1397c5933b989
14481c788dcb3
1524707e5858d
hex134866b3565

1325105100133 has 2 divisors, whose sum is σ = 1325105100134. Its totient is φ = 1325105100132.

The previous prime is 1325105100073. The next prime is 1325105100157. The reversal of 1325105100133 is 3310015015231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1297772083204 + 27333016929 = 1139198^2 + 165327^2 .

It is a cyclic number.

It is not a de Polignac number, because 1325105100133 - 237 = 1187666146661 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1325105100098 and 1325105100107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1325105100173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662552550066 + 662552550067.

It is an arithmetic number, because the mean of its divisors is an integer number (662552550067).

Almost surely, 21325105100133 is an apocalyptic number.

It is an amenable number.

1325105100133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325105100133 is an equidigital number, since it uses as much as digits as its factorization.

1325105100133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 25.

The spelling of 1325105100133 in words is "one trillion, three hundred twenty-five billion, one hundred five million, one hundred thousand, one hundred thirty-three".