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13251252224141 is a prime number
BaseRepresentation
bin1100000011010100110000…
…1011101000000010001101
31201220210210112212221222122
43000311030023220002031
53214102031032133031
644103312523422325
72535241245306401
oct300651413500215
951823715787878
1013251252224141
11424990846a528
1215a02216849a5
137517842c5329
1433b514c7d101
1517ea673a547b
hexc0d4c2e808d

13251252224141 has 2 divisors, whose sum is σ = 13251252224142. Its totient is φ = 13251252224140.

The previous prime is 13251252224137. The next prime is 13251252224149. The reversal of 13251252224141 is 14142225215231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9524599578025 + 3726652646116 = 3086195^2 + 1930454^2 .

It is a cyclic number.

It is not a de Polignac number, because 13251252224141 - 22 = 13251252224137 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13251252224149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625626112070 + 6625626112071.

It is an arithmetic number, because the mean of its divisors is an integer number (6625626112071).

Almost surely, 213251252224141 is an apocalyptic number.

It is an amenable number.

13251252224141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13251252224141 is an equidigital number, since it uses as much as digits as its factorization.

13251252224141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 38400, while the sum is 35.

Adding to 13251252224141 its reverse (14142225215231), we get a palindrome (27393477439372).

The spelling of 13251252224141 in words is "thirteen trillion, two hundred fifty-one billion, two hundred fifty-two million, two hundred twenty-four thousand, one hundred forty-one".