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13251300000000 = 2835844171
BaseRepresentation
bin1100000011010100111100…
…0001111000000100000000
31201220210220212210020010220
43000311033001320010000
53214102130300000000
644103321351423040
72535242365351536
oct300651701700400
951823825706126
1013251300000000
114249932431207
1215a0235684a80
1375179118227a
1433b51b358156
1517ea6b6911a0
hexc0d4f078100

13251300000000 has 324 divisors, whose sum is σ = 44085703990608. Its totient is φ = 3533600000000.

The previous prime is 13251299999863. The next prime is 13251300000031. The reversal of 13251300000000 is 315231.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 299977915 + ... + 300022085.

Almost surely, 213251300000000 is an apocalyptic number.

13251300000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13251300000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22042851995304).

13251300000000 is an abundant number, since it is smaller than the sum of its proper divisors (30834403990608).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13251300000000 is an frugal number, since it uses more digits than its factorization.

13251300000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44230 (or 44181 counting only the distinct ones).

The product of its (nonzero) digits is 90, while the sum is 15.

Adding to 13251300000000 its reverse (315231), we get a palindrome (13251300315231).

The spelling of 13251300000000 in words is "thirteen trillion, two hundred fifty-one billion, three hundred million", and thus it is an aban number.